### Challenge

Quantum computing is so interesting! |

File : quantum_game.py

### Solution

#### Stage1

for i in range(100): |

In stage 1, Allow us to use two gates to rotate qbit.

def rand_choice(): |

`rand_choice`

will spin on X-axis.

In `choice1`

, we can place `Hadamard gate`

first.

Change `initial state (+Z)`

to `+X`

, then `rand_choice`

will do nothing with it.

then we put `Hadamard gate`

again in `choice2`

, the state will go back to `+Z`

Finally, put `X gate`

in the end to make `+Z`

spin to `-Z`

The measurement will always be `1`

#### Stage 2

your_choice = self.get_choice() |

In stage 2, this challenge require you to defeat your solution in stage 1.

this challenge is: `H + ? + H + X`

In this case, spin `Y-axis`

is well. `H + Y + H + X`

will make everything go back to `0`

.

#### Stage 3

target = random.randint(1000, 99000) |

In stage 3, this time they require your to turn as many head coin as they are.

We must find out what the axis they use.

The probability that the state of the angle t with the X axis on the YZ plane is 1 is `sin(t/2)^2`

.

we have known that the probability is `target/100000 * 100`

.

so, we can reverse it : `2 * np.arcsin(np.sqrt(target / 100000))`